From 31bef7b0bcc958560d8072508aac4a95ba0c37e5 Mon Sep 17 00:00:00 2001 From: wuzhiyu5 Date: Sat, 28 Apr 2018 15:14:33 +0800 Subject: [PATCH] =?UTF-8?q?=E8=B0=83=E6=95=B4=E6=8F=8F=E8=BF=B0=E4=BB=A5?= =?UTF-8?q?=E7=AC=A6=E5=90=88=E4=BC=AA=E4=BB=A3=E7=A0=81=E4=B8=AD=E5=B1=95?= =?UTF-8?q?=E7=A4=BA=E5=86=85=E5=AE=B9?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- docs/spec.md | 56 ++++++++++++++++++++++++++-------------------------- 1 file changed, 28 insertions(+), 28 deletions(-) diff --git a/docs/spec.md b/docs/spec.md index 3d0cea9..a700587 100644 --- a/docs/spec.md +++ b/docs/spec.md @@ -124,18 +124,18 @@ ES6 规格将这个标准流程，使用简写的方式表达。 > 1. ReturnIfAbrupt(x). > 1. ReturnIfAbrupt(y). > 1. If `Type(x)` is the same as `Type(y)`, then -> 1. Return the result of performing Strict Equality Comparison `x === y`. +> 1. Return the result of performing Strict Equality Comparison `x === y`. > 1. If `x` is `null` and `y` is `undefined`, return `true`. > 1. If `x` is `undefined` and `y` is `null`, return `true`. -> 1. If `Type(x)` is Number and `Type(y)` is String,
+> 1. If `Type(x)` is Number and `Type(y)` is String, > return the result of the comparison `x == ToNumber(y)`. -> 1. If `Type(x)` is String and `Type(y)` is Number,
+> 1. If `Type(x)` is String and `Type(y)` is Number, > return the result of the comparison `ToNumber(x) == y`. > 1. If `Type(x)` is Boolean, return the result of the comparison `ToNumber(x) == y`. > 1. If `Type(y)` is Boolean, return the result of the comparison `x == ToNumber(y)`. -> 1. If `Type(x)` is either String, Number, or Symbol and `Type(y)` is Object, then
+> 1. If `Type(x)` is either String, Number, or Symbol and `Type(y)` is Object, then > return the result of the comparison `x == ToPrimitive(y)`. -> 1. If `Type(x)` is Object and `Type(y)` is either String, Number, or Symbol, then
+> 1. If `Type(x)` is Object and `Type(y)` is either String, Number, or Symbol, then > return the result of the comparison `ToPrimitive(x) == y`. > 1. Return `false`. @@ -229,17 +229,17 @@ a2.map(n => 1) // [, , ,] > 1. `ReturnIfAbrupt(A)`. > 1. Let `k` be 0. > 1. Repeat, while `k` < `len` -> 1. Let `Pk` be `ToString(k)`. -> 1. Let `kPresent` be `HasProperty(O, Pk)`. -> 1. `ReturnIfAbrupt(kPresent)`. -> 1. If `kPresent` is `true`, then -> 1. Let `kValue` be `Get(O, Pk)`. -> 1. `ReturnIfAbrupt(kValue)`. -> 1. Let `mappedValue` be `Call(callbackfn, T, «kValue, k, O»)`. -> 1. `ReturnIfAbrupt(mappedValue)`. -> 1. Let `status` be `CreateDataPropertyOrThrow (A, Pk, mappedValue)`. -> 1. `ReturnIfAbrupt(status)`. -> 1. Increase `k` by 1. +> 1. Let `Pk` be `ToString(k)`. +> 1. Let `kPresent` be `HasProperty(O, Pk)`. +> 1. `ReturnIfAbrupt(kPresent)`. +> 1. If `kPresent` is `true`, then +> 1. Let `kValue` be `Get(O, Pk)`. +> 1. `ReturnIfAbrupt(kValue)`. +> 1. Let `mappedValue` be `Call(callbackfn, T, «kValue, k, O»)`. +> 1. `ReturnIfAbrupt(mappedValue)`. +> 1. Let `status` be `CreateDataPropertyOrThrow (A, Pk, mappedValue)`. +> 1. `ReturnIfAbrupt(status)`. +> 1. Increase `k` by 1. > 1. Return `A`. 翻译如下。 @@ -254,20 +254,20 @@ a2.map(n => 1) // [, , ,] > 1. 如果报错就返回 > 1. 设定`k`等于 0 > 1. 只要`k`小于当前数组的`length`属性，就重复下面步骤 -> 1. 设定`Pk`等于`ToString(k)`，即将`K`转为字符串 -> 1. 设定`kPresent`等于`HasProperty(O, Pk)`，即求当前数组有没有指定属性 -> 1. 如果报错就返回 -> 1. 如果`kPresent`等于`true`，则进行下面步骤 -> 1. 设定`kValue`等于`Get(O, Pk)`，取出当前数组的指定属性 -> 1. 如果报错就返回 -> 1. 设定`mappedValue`等于`Call(callbackfn, T, «kValue, k, O»)`，即执行回调函数 -> 1. 如果报错就返回 -> 1. 设定`status`等于`CreateDataPropertyOrThrow (A, Pk, mappedValue)`，即将回调函数的值放入`A`数组的指定位置 -> 1. 如果报错就返回 -> 1. `k`增加 1 +> 1. 设定`Pk`等于`ToString(k)`，即将`K`转为字符串 +> 1. 设定`kPresent`等于`HasProperty(O, Pk)`，即求当前数组有没有指定属性 +> 1. 如果报错就返回 +> 1. 如果`kPresent`等于`true`，则进行下面步骤 +> 1. 设定`kValue`等于`Get(O, Pk)`，取出当前数组的指定属性 +> 1. 如果报错就返回 +> 1. 设定`mappedValue`等于`Call(callbackfn, T, «kValue, k, O»)`，即执行回调函数 +> 1. 如果报错就返回 +> 1. 设定`status`等于`CreateDataPropertyOrThrow (A, Pk, mappedValue)`，即将回调函数的值放入`A`数组的指定位置 +> 1. 如果报错就返回 +> 1. `k`增加 1 > 1. 返回`A` -仔细查看上面的算法，可以发现，当处理一个全是空位的数组时，前面步骤都没有问题。进入第 10 步的 ii 时，`kPresent`会报错，因为空位对应的属性名，对于数组来说是不存在的，因此就会返回，不会进行后面的步骤。 +仔细查看上面的算法，可以发现，当处理一个全是空位的数组时，前面步骤都没有问题。进入第 10 步中第 2 步时，`kPresent`会报错，因为空位对应的属性名，对于数组来说是不存在的，因此就会返回，不会进行后面的步骤。 ```javascript const arr = [, , ,];