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调整描述以符合伪代码中展示内容

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wuzhiyu5 2018-04-28 15:14:33 +08:00 committed by ruanyf
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10
docs/spec.md
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@ -127,15 +127,15 @@ ES6 规格将这个标准流程，使用简写的方式表达。
> 1. Return the result of performing Strict Equality Comparison `x === y`.
> 1. If `x` is `null` and `y` is `undefined`, return `true`.
> 1. If `x` is `undefined` and `y` is `null`, return `true`.
> 1. If `Type(x)` is Number and `Type(y)` is String,</br>
> 1. If `Type(x)` is Number and `Type(y)` is String,
> return the result of the comparison `x == ToNumber(y)`.
> 1. If `Type(x)` is String and `Type(y)` is Number,</br>
> 1. If `Type(x)` is String and `Type(y)` is Number,
> return the result of the comparison `ToNumber(x) == y`.
> 1. If `Type(x)` is Boolean, return the result of the comparison `ToNumber(x) == y`.
> 1. If `Type(y)` is Boolean, return the result of the comparison `x == ToNumber(y)`.
> 1. If `Type(x)` is either String, Number, or Symbol and `Type(y)` is Object, then</br>
> 1. If `Type(x)` is either String, Number, or Symbol and `Type(y)` is Object, then
> return the result of the comparison `x == ToPrimitive(y)`.
> 1. If `Type(x)` is Object and `Type(y)` is either String, Number, or Symbol, then</br>
> 1. If `Type(x)` is Object and `Type(y)` is either String, Number, or Symbol, then
> return the result of the comparison `ToPrimitive(x) == y`.
> 1. Return `false`.
@ -267,7 +267,7 @@ a2.map(n => 1) // [, , ,]
> 1. `k`增加 1
> 1. 返回`A`
仔细查看上面的算法，可以发现，当处理一个全是空位的数组时，前面步骤都没有问题。进入第 10 步的 ii 时，`kPresent`会报错，因为空位对应的属性名，对于数组来说是不存在的，因此就会返回，不会进行后面的步骤。
仔细查看上面的算法，可以发现，当处理一个全是空位的数组时，前面步骤都没有问题。进入第 10 步中第 2 步时，`kPresent`会报错，因为空位对应的属性名，对于数组来说是不存在的，因此就会返回，不会进行后面的步骤。
```javascript
const arr = [, , ,];